Python中unicode码转utf8的方法

Python #编码转换2012-11-25 22:36

代码如下：

def h2b(x):
	"""十六进制转二进制 http://yige.org"""
	result = []
	if x==0:
		return ['0']
	while x != 1:
		result.append(str(x%2))
		x /= 2
	result.append('1')
	result.reverse()
	if len(result) % 4 != 0:
		for i in range(0,(4 - len(result) % 4)):
			result.insert(0,'0')
	return "".join(result)

def c2u(x):
	"""unicode 转 utf8"""
	result = ''
	if 0x0 <= x and x <= 0x7F:
		result =  h2b(x)
	elif 0x80 <= x and x <= 0x7FF:
		if len(h2b(x)) == 8:
			tmp = '000' + h2b(x)
		else:
			tmp = h2b(x)[1:]
		result = '110'+ tmp[0:5] + '10' + tmp[5:]
	elif 0x800 <= x and x <= 0xFFFF:
		if len(h2b(x)) == 12:
			tmp = '0000' + h2b(x)
		else:
			tmp = h2b(x)
		result = '1110'+ tmp[0:4] + '10' + tmp[4:10] + '10' + tmp[10:]
	return b2h(result)

def b2h(x):
	"""二进制转十六进制"""
	hex = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9' , 'A' , 'B' , 'C' , 'D' , 'E' , 'F']
	result = []
	def getValue(bin):
		value = 0
		for i in range(4):
			value += int(bin[i]) * 2**(3-i)
		return value
	for i in range(len(x)/4):
		result.append(hex[getValue(x[i*4:(i+1)*4])])
	return result

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Python中unicode码转utf8的方法

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